55places.com was out Monday with its list of the 20 most affordable places to retire in 2019.

In order to pinpoint the top locations, 55places measured a series of factors, including overall cost of living, median home prices, state tax laws, local health care options, availability of 55+ communities, and public transit, among other variables. The cities named not only offer reasonable housing costs, but also provide exciting amenities and healthy living options.

Hand-out 55places.com

The most affordable places to retire in 2019 include:
1 Sioux Falls, South Dakota
2 Ocala, Florida
3 Lakeland, Florida
4 Jacksonville, Florida
5 Daytona Beach, Florida
6 Gainesville, Florida
7 New Castle County, Delaware
8 South Bend, Indiana
9 Tampa, Florida
10 Waco, Texas
11 Birmingham, Alabama
12 Memphis, Tennessee
13 San Antonio, Texas
14 Ft. Myers-Cape Coral, Florida
15 Phoenix, Arizona
16 Melbourne, Florida
17 Grand Rapids, Michigan
18 Orlando, Florida
19 Wichita Falls, Texas
20 Indianapolis, Indiana

The list also comes after the company surveyed its readers to uncover expectations for buying a retirement home. When asked about anticipated costs of a future home compared to the value of their current one, 26% respondents answered "about the same," 27% said "slightly less" and 24% said "much less."

"This information tells us 77% of active adults need their next home to be affordable," said Danny Goodman, COO and co-founder of 55places.com. "But a home within a certain price point is only half of the equation. The surrounding area—whether or not an active adult community is of interest—plays an integral role in quality of life, and nearby attractions and available establishments can greatly enhance that. These destinations provide budget-friendly options without demanding a sacrifice for comfort."